tag:blogger.com,1999:blog-6124489411137620600.post775925838894626936..comments2023-05-04T04:35:41.461-04:00Comments on Baseball Nooby: Yestps12http://www.blogger.com/profile/17835159324328838489noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-6124489411137620600.post-67887859884183745122008-12-05T23:06:00.000-05:002008-12-05T23:06:00.000-05:00What an excellent blog post. Now, can you help me ...What an excellent blog post. <BR/><BR/>Now, can you help me show that the sum from n = -(N-1)/2 to (N-1)/2 of e^(j*n*k*d*sin(theta)) is equal to 1/N * sin(1/N*k*d*sin(theta))/sin(1/(2*k*d*sin(theta)) ? awesome! thanks.Davehttps://www.blogger.com/profile/14854096881452687343noreply@blogger.com